# Why are possible bounties only multiples of 50?

In this community there are also more convenient values: 64, 256, 1024 or even 1729. So what is the reason of providing bounties being only steps of 50?

Edit From the comments I understand, that my original question is unclear. I want to ask, why there is the step greater than one, not any number greater than a chosen threshold?

• Good thing you asked this here and not on Meta.SO! :) This is most certainly status-by-design since they provide a combo-box to make a selection. – Werner Oct 27 '13 at 3:09
• why convenient? Are you using a binary keyboard? – percusse Oct 27 '13 at 17:40
• You could also ask: Why is the meta site grey? 50 seems like an arbitrary number. Would you have asked the question if bounties were multiples of 51? – jub0bs Oct 27 '13 at 20:10
• Because humans use the decimal numeral system. Fifty is half of 10^2 (you need to start somewhere). And 50 is just a value that is acceptable as a minimum bounty value (in relation to the reputation system). Quote: “Besides the anniversary, all multiples of 100, 50, 25, 10 or even 5 are jubilees. The jubilee is more meaningful, the more it can be divided by those numbers without remainder.” – Qrrbrbirlbel Oct 28 '13 at 7:09
• I know 1729 has significance to mathematicians as the smallest number that can be written as a sum of two cubes in two different ways, but is there any special significance to the TeX/LaTeX community? – Charles Staats Oct 28 '13 at 17:16
• @Jubobs It is strange for me, why the step is 50, not 1. – Przemysław Scherwentke Oct 30 '13 at 18:58
• @CharlesStaats If Fermat hypothesis (now theorem) appears in Knuth's book, any other connection with matmematics may be meaningful. – Przemysław Scherwentke Oct 30 '13 at 19:03
• Why do we have 10 fingers rather than 12 or more? – kiss my armpit Nov 3 '13 at 14:15
• I always wanted to offer a bounty of 28.63 – Nicholas Hamilton Nov 14 '13 at 11:53